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I have a column with 14000+ rows and there is only two numbers in this column.

for i  in df['Yes/No']:
  
  if(i in "Yes"):
    y_counter += 1

  else:
    n_counter += 1

When I try this I get an equal 12/12 return for each counter. That is definitely not correct. How do I loop through and count the Yes and Nos?

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    df['Yes/No'].value_counts() Commented Mar 31, 2022 at 16:20

1 Answer 1

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You can do it like this :

y_counter = (data['Yes/No'] == 'yes').sum()
n_counter = (data['Yes/No'] == 'no').sum()
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