Here is a problem which bothers me - I need to read version number from user input, and I'd like to create a "menu" using the length of the array storing the version numbers. However, BASH's mysterious syntax is not helping me here:
echo $VERSIONS
2.0.10-1 2.0.7-1 2.0.7-1 2.0.7-1 2.0.10-1
for v in ${!VERSIONS[*]}
do
echo "$(($v+1))) ${VERSIONS[$v]} "
done
output
1) 2.0.10-1
2.0.7-1
2.0.7-1
2.0.7-1
2.0.10-1
2) 2.0.7-1
3) 2.0.7-1
4) 2.0.7-1
5) 2.0.10-1
another command
for v in ${!VERSIONS[*]}
do
echo "$(($v+1))) ${VERSIONS[$v+1]} "
done
1) 2.0.7-1
2) 2.0.7-1
3) 2.0.7-1
4) 2.0.10-1
5)
What I'd really like to have is an output like that:
1) 2.0.7-1
2) 2.0.7-1
3) 2.0.7-1
4) 2.0.10-1
with out the last 5)....
Would be happy to unravel how to do it in bash...
P.S. A colleague of mine just offered a way without arrays. I'm posting it just for fun:
i=1
for v in $VERSIONS
do
echo "$i) $v" ; i=$(($i+1))
done
output
1) 2.0.10-1
2) 2.0.7-1
3) 2.0.7-1
4) 2.0.7-1
5) 2.0.10-1
OK, since the solutions don't work inside my script I will post some more info:
for package in $NEWPACKAGES
do
apt-show-versions -a -p $package
VERSIONS=$(apt-show-versions -a -p $package | cut -d ":" -f 2 | cut -d " " -f 1)
echo $VERSIONS
echo "type the number for version you want to install: (type enter to skip)"
for i in `seq 1 ${#VERSIONS[@]}`; do
echo "$i) ${VERSIONS[$(($i-1))]}";
done
echo $VERSIONS
read version
echo "your choice $version"
# now the problem is that i can't get this part to work !
apt-get install $package="${#VERSIONS[$version]}"
done
array=($VERSIONS)