I'm searching some files with: find . -name "*.en.php" and find . -name "*.fr.php".
I want both commands in the same line, something like : find . -name "*.(en|fr).php" but it doesn't work.
Thanks in advance for your help.
EDIT
my command is like this : find . -not -path Config -name "*.fr.php", is there a solution do not repeat -not -path Config ?
Try:
find -name "*.en.php" -o -name "*.fr.php"
If you for example want to run command on each found file, than you need to additional ()
(this will count num of lines in all found files):
find \( -name "*.en.php" -o . -name "*.fr.php" \) -exec cat {} \; | wc -l
You should be able to combine expression with an or operator, thus:
find . -name '*.en.php' -o -name '*.fr.php' ...
You can see all the operators in the man page listed under OPERATORS (and, or, not, parentheses and so forth).
Use the find -o operator, eg.
find . -name "*.en.php" -o -name "*.fr.php"
Edit:
Like so:
find . -path './Config' -prune -o \( -name "*.en.php" -o -name "*.fr.php" \)
The default operator in find (if one is ommited) is and, the parentheses group the name expression. I've added -prune to prevent find from recursing into the Config directory.
