JavaScript json values

Question

Using JavaScript; how do I produce this output

cell
work (123) 456 7890

from this valid json

{"phone": [
{
    "@attributes": {
        "type": "cell",
        "ext": ""
    }
}, "(123) 456 7890", {
    "@attributes": {
        "type": "work",
        "ext": ""
    }
}
]}

Who created that abomination of a JSON document? It should be [{"type": "cell"}, {"type": "work", "number":"(123) 456 7890"}]. This looks to be automatically generated from an XML document. If that's the case, you should parse that XML instead. — phihag
– phihag, Commented Aug 26, 2011 at 10:30
@phihag php json_encode from <phone type="cell" ext=""></phone> <phone type="work" ext="">(123) 456 7890</phone> — tnt-rox
– tnt-rox, Commented Aug 26, 2011 at 10:35
json.org/js.html ... phone is an array. You want to access the second element. I don't see where the problem could be? — Felix Kling
– Felix Kling, Commented Aug 26, 2011 at 10:36
Actually, it looks like it might be VCard data that's been converted to XML and then to JSON… if so, yaiks — Flambino
– Flambino, Commented Aug 26, 2011 at 10:37

Flambino · Accepted Answer · 2011-08-26 10:44:53Z

1

In a very narrow sense, you'd need to do this

var jsonObj = JSON.parse(jsonString);

var type = jsonObj.phone[0]['@attributes'].type // "cell"
var phoneNumber = jsonObj.phone[1] // "(123) 456 7890"

But the structure of that JSON data may change, so you can't rely on the 0/1 indexes, and anyway the structure is weird. Like the comments say, if it comes from XML, then parse that instead

answered Aug 26, 2011 at 10:44

Flambino

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Community · Accepted Answer · 2017-05-23 09:59:08Z

0

I see you kind of duplicate question from: Access json value using JavaScript object notation Simple loop could help:

var tel;
for (var i=0,l=phone.length; i<l; i++) {
  if (phone[i]['@attributes']) {
    if (phone[i-1] && typeof phone[i-1]==='string') {
      tel = phone[i-1];
    } else {
      tel = '';
    }
    console.log(phone[i]['@attributes'].type+' '+tel);
  }

But the guys above are right, if the structure changed a bit, this code will probably won't work.

edited May 23, 2017 at 9:59

CommunityBot

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answered Aug 26, 2011 at 10:45

muffir

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1 Comment

tnt-rox Over a year ago

sorry about the dupe, trying to get my head around the problem. thanks tho!

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