const items = [ { 'first': [205, 208, 222] }, { 'second': 205 } ]
I need to find keys by all coincidence into its value/values
example:
find key by id=205, output: 'first', 'second'
find key by id=208, output: 'first'
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1the output is form of array ?brk– brk2022-05-04 05:59:11 +00:00Commented May 4, 2022 at 5:59
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1'second': 205, shouldn't this be an array?Tushar Shahi– Tushar Shahi2022-05-04 06:01:07 +00:00Commented May 4, 2022 at 6:01
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yes, output should be an arraysimplesample– simplesample2022-05-04 08:53:47 +00:00Commented May 4, 2022 at 8:53
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4 Answers
You can do something like this
const items = [ { 'first': [205, 208, 222] }, { 'second': 205 } ]
const findKey = (data, value) => data.reduce((res, item) => {
let [[key, v]] = Object.entries(item)
v = Array.isArray(v)?v: [v]
if(v.includes(value)){
return [...res, key]
}
return res
}, [])
console.log(findKey(items, 205))
console.log(findKey(items, 208))
Comments
You can try getting the arrays of keys and values, then filter the keys and check if the corresponding index in values contain the variable id.
const items = [ { 'first': [205, 208, 222] }, { 'second': 205 } ]
const id = 205;
let keys = items.map(item => Object.keys(item)[0]);
let values = items.map(item => Object.values(item)[0]);
let output = keys.filter((_, index) => (values[index] == id || (typeof(values[index]) == 'object' && values[index].includes(id))));
console.log(output)
Comments
You can click on 'Run code snippet' and see the output as mentioned in the question
const items = [{
first: [205, 208, 222],
},
{
second: 205,
},
];
const toFind = 205;
const fin = items.reduce((finalOutput, item) => {
let key = Object.keys(item)[0];
if (Array.isArray(item[key])) {
if (item[key].includes(toFind)) finalOutput.push(key);
} else if (item[key] === toFind) {
finalOutput.push(key);
}
return finalOutput;
}, []);
console.log(fin);
Comments
Format your items data properly, then:
const items = [ { 'first': [205, 208, 201] }, { 'second': [205] } ]
const findKeys = n => items.reduce((acc, obj) =>
Object.values(obj).some(arr => arr.includes(n)) ?
acc.concat(Object.keys(obj)) :
acc,
[])
const res = findKeys(208)
// Output: ['first']
console.log(res)
