Powershell script to create folder for groups with extensionAttribute1 set

Question

Hi I want to write a powershell scrip that creates a folder for groups in a specific OU where I have set the extensionAttribute1.

Get-ADGroup -filter * -SearchBase "OU=Groups,OU=Test,DC=test,DC=Domain,DC=en" -properties * | where {$_.extensionAttribute1}| select-object samaccountname, extensionAttribute1

so I get the list of groups with extensionAttribute1 and with

Get-ChildItem D:\Test

I get the list of already created folders. What is the best way to compare these two lists and create one for the groups for which no folder is created yet?

So, to rephrase, you're looking to compare the group names from Get-ADGroup, to the folder names returned by Get-ChildItem D:\Test? Then, create the folders based on which one's missing? — Abraham Zinala
– Abraham Zinala, Commented May 4, 2022 at 12:56
the idea is that for a group (e.g. Test) if the extensionAttribute1 is set to folder, a new folder with the group names is created on the server drive D:\ if no folder exists yet — Sven
– Sven, Commented May 5, 2022 at 13:10
That's still confusing, probably why noone has answered yet lol. You want a single folder for the group names, or separate folders per group that has the value of Folder in extensionAttribute1? — Abraham Zinala
– Abraham Zinala, Commented May 5, 2022 at 13:30
I would like to create a new directory for each group where the atriubet is set that has the group name. and of course the script should not try to create a folder if it already exists — Sven
– Sven, Commented May 6, 2022 at 14:29

Abraham Zinala · Accepted Answer · 2022-05-10 01:40:47Z

0

Given you're scenario, you don't have to use Get-ChildItem if you just want to see if the folder already exists. Then, you would only need Test-Path and use a loop to test for each folder.

Get-ADGroup -filter * -SearchBase "OU=Groups,OU=Test,DC=test,DC=Domain,DC=en" -properties "extensionAttribute1" | 
    Where-Object -FilterScript { $_.extensionAttribute1 -eq "Folder" } | 
    ForEach-Object `
        -Begin { $path = "D:\Test\"  } `
        -Process {
            if (-not (Test-Path -LiteralPath ($path + $_.Name))) {
                New-Item -Path $path -Name $_.Name -ItemType "Directory" | Out-Null 
            }
        }

edited May 10, 2022 at 1:40

answered May 9, 2022 at 22:06

Abraham Zinala

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