How to open my flutter app by clicking a url

Question

I'm working on a flutter app, and now I need to be able to open my app whenever a URL with a certain pattern is clicked.

In other words, I'd like to have that option from a clicked URL saying "Which app do you want to use to open this link"

and from the shown apps to open this link I want mine to be in there

Is it possible? How can I do this?

Also, I need to say I have done this from Android Studio - Java, but never in flutter/dart, I am a newbie around flutter

Do you just mean a web app using Flutter? Or Android, iOS, Windows app too? — Roslan Amir
– Roslan Amir, Commented May 6, 2022 at 15:46
Sorry. I have no idea how you open an Android app using a URL. AFAIK, you install an Android app on an Android device. — Roslan Amir
– Roslan Amir, Commented May 7, 2022 at 5:20
Haven't you pressed a url in your phone and it says "Open with" and you have a list of apps? let's say Opera/Chrome/Telegram, and as it is a telegram invitation link you press telegram to open it? — Devck - DC
– Devck - DC, Commented May 7, 2022 at 9:58

david okoroafor · Accepted Answer · 2025-07-14 07:18:42Z

4

I have found the solution, this link is going to give you everything you need for deep linking in flutter:

Documentation/Installation

edited Jul 14 at 7:18

david okoroafor

3651 silver badge9 bronze badges

answered May 7, 2022 at 10:23

Devck - DC

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Comments

ldpereira · Accepted Answer · 2024-06-13 02:11:39Z

2

The library mentioned was discontinued. This is the new one: https://pub.dev/packages/app_links

answered Jun 13, 2024 at 2:11

ldpereira

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