I want to make a button that will create a back page if I click this it will return to the last div content. I already have the function for the next page but I'm already ran out of logic for making a function for the back page button.
Here is my code for the content and my function for the next()
function next() {
if ($('#content1').hasClass('')) {
$('#content2').removeClass('hidden');
$('#back').removeClass('hidden');
$('#content1').addClass('hidden');
} else if ($('#content2').hasClass('')) {
$('#content2').addClass('hidden');
$('#content3').removeClass('hidden');
} else if ($('#content3').hasClass('')) {
$('#content3').addClass('hidden');
$('#content4').removeClass('hidden');
} else if ($('#content4').hasClass('')) {
$('#content4').addClass('hidden');
$('#content5').removeClass('hidden');
}
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js"></script>
<div class="myDiv">
<div id="content1">
<h1>1</h1>
</div>
<div id="content2" class="hidden">
<h1>2</h1>
</div>
<div id="content3" class="hidden">
<h1>3</h1>
</div>
<div id="content4" class="hidden">
<h1>4</h1>
</div>
<div id="content5" class="hidden">
<h1>5</h1>
</div>
<button onclick='next()'>Next Page</button>
<button id="back" onclick='back()' class="hidden">Back Page</button>
</div>