Add additional character filter to regular expression

Question

I have regular expression which is checking for at least one character or number:

^(?=.*[a-zA-Z])(?=.*[0-9]).*$

I want to add one more condition there to exclude forward slash:

I know that to exclude forward slash would be something like that [^/] but i don't know how exactly put it to my regex.

May be someone may help me with that?

Tim Pietzcker · Accepted Answer · 2011-08-29 12:27:12Z

2

^(?=.*[a-zA-Z])(?=.*[0-9])[^/]*$

That's all there is to it.

The dot . means "any character". The * repeats the previous token 0 or more times. So

[^/]*

means "zero or more non-slash characters", whereas

[^/].*

means "one non-slash character, followed by zero or more characters of any kind".

answered Aug 29, 2011 at 12:11

Tim Pietzcker

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4 Comments

i tried like that but didn't took out the comma ^(?=.*[a-zA-Z])(?=.*[0-9])[^/].*$ , what comma means?

the last dot, this one before $, I quoted how i was trying to exclude forward slash

hehe, me as well, i mean dot not comma :)

when i leave the dot after [^/] this dot means what?