Two different objects with same code-scripts in Unity work differently

Question

I've got this part of script

void Update()
    {
        if (Pause_Menu.retryed)
        {
            Debug.Log(this.name);
            Destroy(this);
        }
    }

It is attached to two object, but no matter which object exists, the first of them is still will be not destroyed and console will stay empty and the second one will be destroyed and console will has his name. What kind of problem it can be?

And also strange thing. If I'm trying destroy the first and the second externally by GameObject.Find() I will find also one of them, like second even doesn't exist, but it does.

Destroy(this); will destroy the component, so if you intended to destroy the game object you need Destroy(gameObject); — Everts
– Everts, Commented May 24, 2022 at 11:22
@Everts Thanks. But then I don't understand, this method still works for the first object, but not the second. And if I replace it on Debug.Log(this.gameObject.name); and Destroy(this.gameObject); it doesn't change something — Chamistery
– Chamistery, Commented May 24, 2022 at 11:30
The first GameObject is inactive, or this component is disabled, or Pause_Menu.retryed is false. — shingo
– shingo, Commented May 24, 2022 at 11:37
@shingo Thanks, I thought the same, but I've checked literally hundred times, both of them are active — Chamistery
– Chamistery, Commented May 24, 2022 at 11:40

Chamistery · Accepted Answer · 2022-05-24 12:59:55Z

1

Yah, the problem was in difference between gameObject and component, I used it wrong. Thanks everyone and especially @Everts!

answered May 24, 2022 at 12:59

Chamistery

213 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Two different objects with same code-scripts in Unity work differently

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related