Using javax.xml.xpath. with scala.xml

Question

Is it possible to use javax.xml.xpath.XPathExpressions with scala.xml.NodeSeqs?

I'd like an API that allows me to express something like:

val xml = ...
val xpath = XPathFactory.newInstance.newXPath.compile(
    """/this/that/theOther[@abc="123"]""")
val selectedNodes: NodeSeq = xml.applyXpath(xpath)

Yuriy Zubarev · Accepted Answer · 2011-08-30 04:54:33Z

2

Scala takes a functional approach to searching through XML. In same cases it's not as clear as XPath and takes some getting used to it. For example:

scala> val myXml = <books><book category="1">first</book><book category="2">second</book><book category="1">third</book></books>
myXml: scala.xml.Elem = <books><book category="1">first</book><book category="2">second</book><book category="1">third</book></books>

scala> (myXml \ "book").filter { node => (node \\ "@category").text == "1" }
res24: scala.xml.NodeSeq = NodeSeq(<book category="1">first</book>, <book category="1">third</book>)

answered Aug 30, 2011 at 4:54

Yuriy Zubarev

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3 Comments

Synesso Over a year ago

Thanks, but sorry, that does not address the question: Is there an existing library that mixes javax.xml.xpath with scala.xml

Yuriy Zubarev Over a year ago

You also had the second question: "Is there an alternative?". I answered the second one.

Synesso Over a year ago

The answer to my revised question (because I didn't really care about the alternative) is "No, it is not possible". But have a tick anyway. :)

Chris · Accepted Answer · 2011-11-06 12:37:20Z

1

Is it an absolute requirement that its Scala XML and javax.xml.xpath? Or that you'd rather use string based XPaths within Scala.

Scales Xml has added string based XPath usage (as well as the faster internal syntax) but I haven't yet decided if it makes sense to provide a javax.xml.xpath implementation.

If this is something useful for people I'd consider spending more time on implementing it.

answered Nov 6, 2011 at 12:37

Chris

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1 Comment

Synesso Over a year ago

Yes the latter. I only wanted to use xpaths with Scala. Thank you.

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