How do I filter an array while excluding specific conditions?

Question

I have button that I’m disabling by reading an array and checking its properties.

My array looks like this:

const arr = [
  {id: ‘1’, name: ‘SOME_THING’, status: ‘AGREED’},
  {id: ‘2’, name: ‘THIS_THING’, status: ‘AGREED’},
  {id: ‘3’, name: ‘OTHER_THING’, status: ‘AGREED’},
  {id: ‘4’, name: ‘EVERY_THING’, status: ‘AGREED’},
];

My current logic to disable/enable this button looks like this:

arr.filter((item) => item.indexOf(‘THING’) > -1)
   .every((item) => item.status === ‘AGREED’)

Now my requirements have changed. I want to enable/disable the button in the same way, but I want to EXCLUDE specific elements from this array. For example, I want to exclude these two items:

{id: ‘2’, name: ‘THIS_THING’, status: ‘AGREED’},
{id: ‘3’, name: ‘OTHER_THING’, status: ‘AGREED’},

Using my logic, how do I filter my array while EXCLUDING these two?

I realize I can just try to delete these specific items but I was wondering if there was potentially a cleaner way to do that without explicit deletion.

Did you extent prototype of object? Object doesn't implement indexOf() by default, — Krzysztof Safjanowski
– Krzysztof Safjanowski, Commented Jun 3, 2022 at 14:26

Harvey Kadyanji · Accepted Answer · 2022-06-03 14:16:51Z

2

You can exclude a list of items by always assuming the given key/value pair is true regardless of the value

const exclusionList = ['THIS_THING', 'OTHER_THING'];

arr.filter((item) => item.indexOf(‘THING’) > -1)
   .every((item) => item.status === ‘AGREED’ || exclusionList.includes(item.name))

answered Jun 3, 2022 at 14:16

Harvey Kadyanji

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shubham sharma · Accepted Answer · 2022-06-03 14:33:54Z

0

Also please add your keyName(name) Where you using indexOf

let arr = [
      {id: '1', name: 'SOME_THING', status: 'AGREED'},
      {id: '2', name: 'THIS_THING', status: 'AGREED'},
      {id: '3', name: 'OTHER_THING', status: 'AGREED'},
      {id: '4', name: 'EVERY_THING', status: 'AGREED'},
      
    ]; 
    const list = ['THIS_THING', 'OTHER_THING'];
    console.log(arr.filter((item) => item.name.indexOf(‘THING’) > -1).every((user) => user.status === 'AGREED' || list.some(user.name)))

answered Jun 3, 2022 at 14:33

shubham sharma

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