I'm trying to use a variable outside of its function in python

Question

I'm not sure how I could get my ans_label to access my ans_string as it is defined within the function ssInterpret().

def ssInterpret():
    #region=(x, y, width, height)
    time.sleep(5)
    myScreenshot = pyautogui.screenshot(region=(400, 320, 800, 500))
    myScreenshot.save(imgPath)

    #reads the image

    img = cv2.imread(imgPath)
    text = pytesseract.image_to_string(img)

    q = text

    #completes the answer search

    results = brainlypy.search(q)
    question = results.questions[0]
    print('URL: '+'https://brainly.com/task/'+str(question.databaseid))
    print('QUESTION:',question)
    print('ANSWER 1:', question.answers[0])
    if question.answers_count == 2:
        print('ANSWER 2:', question.answers[1])

    ans_string = str(question.answers[0])

answer_label = Label(root, text=ans_string)

Your current code never even calls ssInterpret, so that code is never going to run. — Silvio Mayolo
– Silvio Mayolo, Commented Jun 4, 2022 at 21:34

quamrana · Accepted Answer · 2022-06-04 21:34:34Z

1

First, your function needs to return the answer:

def ssInterpret():
    ...  # most of function elided.
    return ans_string

#then call the function 
ans = ssInterpret()
answer_label = Label(root, text=ans)

answered Jun 4, 2022 at 21:34

quamrana

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ArijitKD · Accepted Answer · 2022-06-04 21:45:03Z

1

Initialize ans_string as ans_string = "" at the top of your code. Then add a line global ans_string prior to ans_string = str(question.answers[0]) inside the function ssInterpret(). Call ssInterpret() before answer_label = Label(root, text=ans_string). Your code should now work as expected.

Complete code with modification:

ans_string = ""

def ssInterpret():
    #region=(x, y, width, height)
    time.sleep(5)
    myScreenshot = pyautogui.screenshot(region=(400, 320, 800, 500))
    myScreenshot.save(imgPath)

    #reads the image

    img = cv2.imread(imgPath)
    text = pytesseract.image_to_string(img)

    q = text

    #completes the answer search

    results = brainlypy.search(q)
    question = results.questions[0]
    print('URL: '+'https://brainly.com/task/'+str(question.databaseid))
    print('QUESTION:',question)
    print('ANSWER 1:', question.answers[0])
    if question.answers_count == 2:
        print('ANSWER 2:', question.answers[1])

    global ans_string
    ans_string = str(question.answers[0])

ssInterpret()
answer_label = Label(root, text=ans_string)

answered Jun 4, 2022 at 21:45

ArijitKD

1138 bronze badges

2 Comments

quamrana Over a year ago

Nooooo! Avoiding global variables is easy in this case: just return the string.

ArijitKD Over a year ago

Yeah of course, that's one way of doing it :)

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