How to pass a text file as an argument to a function in python

Question

Here is the code and I am trying to see what I have done wrong. I am new to python functions and linking external files so it would be nice if you could explain your code.

def get_data(filename):

  records = []
 
  with open(filename) as readfile:
    lines = readfile.readlines()
    for line in lines:
      # variable line contains: 
      str_rec = line.split(",") 
      pname = str_rec[0]
      price = int(str_rec[1])
      quantity = int(str_rec[2])
      records.append([pname, price, quantity])

  #caution: indentation
  return records


hell= get_data(data.txt)
print(hell)

data.txt is a link to another file that I am trying to pass as an argument.

data.txt is an object (here not defined). "data.txt" is a string describing the path to the file to open — Achille G
– Achille G, Commented Jun 7, 2022 at 10:24

MrWorldWide · Accepted Answer · 2022-06-07 10:27:02Z

2

open(filename) takes the filename as a string, so you should pass the name as a string, not the actual file.

hell= get_data("data.txt")

answered Jun 7, 2022 at 10:27

MrWorldWide

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