How to write a bash script that runs a customized program?

Question

Here is an example for my customized program which is executed as:

./TestVariance.exe 2 100 10 .9

I want to write a bash script that runs it several times while changing the second argument each time. After searching some answers on SO, I come up with a script like

#!/bin/bash
let d=2
let s=10
let q=9/10
for i in 'seq 100 100 1000'
do 
    ./TestVariance.exe $d $i $s $q;
done

But it seems that the script only call TestVariance.exe without passing any arguments. I wonder what's wrong with my script?

BTW, is there any advice for vscode extensions on bash script?

If you want to provide the list of values for i only literally (and not via parameter), you would write for i in {100..1000..100}. — user1934428
– user1934428, Commented Jul 1, 2022 at 9:09
let q=9/10 will result in q=0. Based on your initial sample I expect you wanted 0.9. You don't actually need to use 'let' when setting variables, so you could simply use 'q=0.9' or look at tools like bc if you really need to do floating point math. — tjm3772
– tjm3772, Commented Jul 1, 2022 at 17:16
@tjm3772 you are right. But when I put q=0.9, the script just tells me it is a syntax error: invalid arithmetic operator (error token is ".9"). I wonder how to overcome this. Edit: I come to realized that I can just put .9 as plain text, now it runs well! — sicheng mao
– sicheng mao, Commented Jul 4, 2022 at 8:02

eugercek · Accepted Answer · 2022-07-01 08:46:28Z

1

It should be

`seq 100 100 1000`

'seq 100 100 1000' is literal.

answered Jul 1, 2022 at 8:46

eugercek

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3 Comments

mouviciel Over a year ago

You can replace backticks by bash command substitution: $(seq 100 100 1000). Or you can replace the whole seq subprocess by bash range: {100..1000..100}.

sicheng mao Over a year ago

Indeed, I thought it was something more complex...

sicheng mao Over a year ago

That's very subtle for me, before I've only used ` in markdown. Thank you very much.

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