Script for a requests to URL

Question

I'm trying to make a custom script that will send a request to the page and test it for availability, if the answer is 200, then I want the answer to be 1, if any other 2, and the metric will not be recorded, tell me how best to do it? Sorry if this is a stupid question, I'm just learning python

import requests
from requests.packages.urllib3.exceptions import InsecureRequestWarning 
import os
import datetime
import pytz

def get_status_ghe():
    url_list = [os.environ.get('http://testurl.com:8080')]
    for i in range(0, len(url_list)):
        if resp.status_code == 200:
            print('ghe0')
        elif resp.status_code != 200:
            print('ghe1')
        else:
            print('ghe2')  
def ghe_request():
    try:
        resp = requests.head('http://testurl.com:8080')
        if resp.status_code == 200:
            return 1
            print(resp)
            print('1')
        else:
            return 0
            print(resp)
            print('0')
    except:
        return 0

None of the print() calls after return will execute, since return exits the function. Move return after the print statements. — Barmar
– Barmar, Commented Jul 21, 2022 at 10:56
Is http://testurl.com:8080 really the name of your environment variable? It looks more like the value. — Barmar
– Barmar, Commented Jul 21, 2022 at 10:57
Either the status code is equal to 200 or it's not equal to 200. What's the other possibilities that you think would trigger ghe2? — Barmar
– Barmar, Commented Jul 21, 2022 at 10:58

Barmar · Accepted Answer · 2022-07-21 11:01:57Z

1

You need to call requests.head() in the loop.

Your second condition should just test for any 2xx value (I assume that's what you mean by "any 2"). Then the else: block will handle all other status codes.

Don't use for i in range(len(url_list)): when you can more simply use for url in url_list:

def get_status_ghe():
    url_list = [os.environ.get('http://testurl.com:8080')]
    for url in url_list:
        resp = requests.head(url)
        if resp.status_code == 200:
            print('ghe0')
        elif 201 <= resp.status_code <= 299:
            print('ghe1')
        else:
            print('ghe2')

answered Jul 21, 2022 at 11:01

Barmar

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