Save output into variable

Question

i have tried for like 30 minutes. Whats wrong with this code ? :( Input :

var = `cat marktplatz.html | grep -m 1 "post" | grep -o -E '\b(jobs/.*htm)' `

Output :

var: command not found

Apart from the spacing issue, this is a useless use of cat. It can be written more succinctly as grep -m 1 "post" < marktplatz.html | grep -o -E '\b(jobs/.*htm)' -- or even as < marktplatz.html grep -m 1 "post" | grep -o -E '\b(jobs/.*htm)' — Keith Thompson
– Keith Thompson, Commented Sep 5, 2011 at 21:54
Thanks Keith, .. i am new to bash and programming. Good to know, that this code can be optimized. Always willing to learn from the experienced guys ;) — reBourne
– reBourne, Commented Sep 6, 2011 at 0:03

Fred Foo · Accepted Answer · 2011-09-05 13:33:22Z

5

var = BLABLA

should be

var=BLABLA

The first form is interpreted as running the command var with = as the first argument.

answered Sep 5, 2011 at 13:33

Fred Foo

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