how to remove an item in a list of list of string using index in python

Question

input:

letters = [['a', 'b', 'c'], ['a', 'b', 'c']]
row= 0
column=0

output

[['b', 'c'], ['a', 'b', 'c']]

I tried to do this:

letters[0].remove(0)

but it gives me a value error, while when I use pop like this:

letters[0].pop(0)

it does what I need but the problem with pop is that it returns me something while I just need the item to be removed

If this column in pandas, It's raising errors because your column getting different length with other columns — Mahdi F.
– Mahdi F., Commented Jul 25, 2022 at 17:31

Caleb Bunch · Accepted Answer · 2022-07-25 17:31:54Z

3

letters = [['a', 'b', 'c'], ['a', 'b', 'c']]

del list1[0][0]

use the del keyword

answered Jul 25, 2022 at 17:31

Caleb Bunch

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Comments

Niclas · Accepted Answer · 2022-07-25 17:34:21Z

1

list.remove() removes an item by value, not by index. So letters[0].remove('b') would work.
Simply deleting a single element with the same syntax, you could address it in any other statement is del which could be used as del letters[0][0]
As @Barmar said: list.pop) can return an element by index and remove it from the list.

answered Jul 25, 2022 at 17:34

Niclas

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Arifa Chan · Accepted Answer · 2022-07-25 17:58:06Z

0

You can try this if you want to delete the element by index value of the list:

del letters[0][0]  # [['b', 'c'], ['a', 'b', 'c']]
del letters[1][0]  # [['a', 'b', 'c'], ['b', 'c']]

or if you want remove specific value in the first occurance:

letters[0].remove('a')  # [['b', 'c'], ['a', 'b', 'c']]
letters[1].remove('a')  # [['a', 'b', 'c'], ['b', 'c']]

answered Jul 25, 2022 at 17:58

Arifa Chan

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