http://site.com/js/script.js?ver=1.0
How can I remove the query arguments from a string like this?
(?ver=1.0)
1
4 Answers
Remove everything after (and including) the first ? character:
$str = 'http://site.com/js/script.js?ver=1.0';
$str = substr($str, 0, strpos($str, '?'));
Comments
$string = str_replace('?ver=1.0', '', $string);
Or if this example only represents a laundry list of additional query values, you could explode on the question mark and your first resulting array key will be the desired string.
$array = explode('?', $string);
echo $array[0]; // http://site.com/js/script.js
Comments
If you need to do this for different, longer, or possibly unknown query strings, take your pick from the following methods:
$substr = substr($string, 0, strpos($string, '?'));
$regex = preg_replace('/\?(.*)/', '', $string);
$array = explode('?', $string);
$str = current($array);
Comments
To remove the question mark and everything after it:
$string = 'http://site.com/js/script.js?ver=1.0';
$string = array_shift( explode('?', $string) );
$_SERVER['SCRIPT_FILENAME']is an easier way to get to your string.