JavaScript Rest operator [duplicate]

Question

I am trying to learn javascript but having trouble in the spread and rest operators. Can't understand whats happening here how dose this take in the taxRate parameter like a singel number when we spred the itemsBought parameter

function addTaxToPrices (taxRate, ...itemsBought)
    {
        return(itemsBought.map(item => item*taxRate));
    }
    let ShoppingCart=addTaxToPrices(1.1,46,89,35,79);
    console.log(ShoppingCart)

That's just the syntax, whenever you use the rest operator it captures all the extra arguments not captured by a named paramater — Samathingamajig
– Samathingamajig, Commented Jul 28, 2022 at 15:16
First argument becomes the taxRate, so the value 1.1 . The rest operator will collect all the arguments past the first one into an array. So itemsBought becomes [46,89,35,79] . — Shilly
– Shilly, Commented Jul 28, 2022 at 15:17
@Shilly thanks i get now So the rest operator is just a spread operator used to at time of declaration of an array that we don't know the size-of ?Thanks a bunch!!!! — Pranshu Sati
– Pranshu Sati, Commented Jul 28, 2022 at 15:31

shortQuestion · Accepted Answer · 2022-07-28 15:19:54Z

0

for my understanding it is nearly the same than if you do:

function addTaxToPrices (taxRate, itemsBought)
    {
        return(itemsBought.map(item => item*taxRate));
    }
itemsBought = [46,89,35,79]
let ShoppingCart=addTaxToPrices(1.1,itemsBought);
console.log(ShoppingCart)

answered Jul 28, 2022 at 15:19

shortQuestion

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