Please help. I need to create this pattern:
* * $ * $ * * $ * $ * $ * $ * * $ * $ * $ * * $ *The best I can do is:
rows = 5
for i in range(0, 1):
for j in range(0, i + 1):
print("*", end=' ')
print("\r")
for i in range(0, rows):
for j in range(0, i + 1):
d = "$"
print("*",d, end=' ')
print("\r")
for i in range(rows, 0, -1):
for j in range(0, i - 1):
print("*", d, end=' ')
print("\r")
But it is not what I need. I desperately need help.
You cna simplify a bit : a loop for the increase from 1 to 4, another for the decrease from 5 to 1, then depend on odd/even values choose the correct symbol
rows = 5
for i in range(1, rows):
for j in range(i):
print('*' if j % 2 == 0 else "$", end=" ")
print()
for i in range(rows, 0, -1):
for j in range(i):
print('*' if j % 2 == 0 else "$", end=" ")
print()
Can be done in one outer loop
rows = 3
for i in range(-rows + 1, rows):
for j in range(rows - abs(i)):
print('*' if j % 2 == 0 else "$", end=" ")
print()
Slightly different approach:
N = 5
result = []
for i in range(N):
s = [('*', '$')[j % 2] for j in range(i+1)]
result.append(s)
print(*s)
for i in range(N-2, -1, -1):
print(*result[i])
You can use the abs function to handle the inflection point with one loop:
print(
*(
' '.join(
'*$'[m % 2]
for m in range(rows - abs(rows - n - 1))
)
for n in range(2 * rows - 1)
),
sep='\n'
)
Or the above in one line, if you prefer:
print(*(' '.join('*$'[m % 2] for m in range(rows - abs(rows - n - 1))) for n in range(2 * rows - 1)), sep='\n')
Demo: https://replit.com/@blhsing/KnowledgeableWellwornProblem