Need to split below string log based on timestamp using regex in python

Question

input - logs = "2018-10-23T09:35:29Z sent message 2018-10-23T09:35:29Z transmit error 2018-10-23T09:49:29Z sent message 2018-10-23T10:01:49Z sent message 2018-10-23T10:05:29Z transmit error"

I want to use regex to split by the timestamp_format = "YYYY-MM-DDThh:mm:ssZ" so I can have a list like this, ["2018-10-23T09:35:29Z sent message", "2018-10-23T09:35:29Z transmit error",...]

Basically I want to filter all transmit errors and create a list of transmit errors. I want to do this in python.

Please help.

import re re.compile(r"\d{4}-\d{2}-\d{2}T\d{2}:\d{2}:\d{2}Z") — Jeff Gruenbaum
– Jeff Gruenbaum, Commented Aug 12, 2022 at 16:08

josh-stackexchange · Accepted Answer · 2022-08-12 16:23:23Z

1

Using Jeff's regex pattern:

logs = "2018-10-23T09:35:29Z sent message 2018-10-23T09:35:29Z transmit error 2018-10-23T09:49:29Z sent message 2018-10-23T10:01:49Z sent message 2018-10-23T10:05:29Z transmit error"
pattern = r"\d{4}-\d{2}-\d{2}T\d{2}:\d{2}:\d{2}Z"

# find the starts of each timestamp
split_indices = [m.start(0) for m in re.finditer(pattern, logs)]

# slice the log from one start to the next
output = [logs[i:j].strip() for i,j in zip(split_indices, split_indices[1:]+[None])]

answered Aug 12, 2022 at 16:23

josh-stackexchange

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