Assigning the value returned by a function to a variable in Python

Question

I began coding in Python recently and encountered a problem assigning the value returned by a function to a variable.

class Combolock:
    def _init_(self,num1,num2,num3):
        self.x = [num1,num2,num3]
    def next(self, state):
        print "Enter combination"
        combo = raw_input(">")
        if combo == self.x[state]:
            print "Correct"
            return 1
        else:
            print "Wrong"
            return 0
    def lock(self):
        currentState = 0
        while currentState < 2:
            temp = next(currentState)
            if temp == 1:
                currentState = currentState + 1
            else:
                currentState = 99
                print "ALARM"

When I call the lock function, I get an error at the line

temp = next(currentState)

saying that an int object is not an iterator.

Andrea Ambu · Accepted Answer · 2011-09-07 18:44:13Z

8

You should use self.next(currentState), as you want the next method in the class scope.

The function next is global and next(obj) works only if obj is an iterator.
You might want to have a look at the yield statement in the python documentation.

edited Sep 7, 2011 at 18:44

answered Sep 7, 2011 at 18:36

Andrea Ambu

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Comments

Michał Šrajer · Accepted Answer · 2011-09-07 18:43:32Z

4

As Andrea (+1) pointed it out you need to tell python you want to call next() method on self object, so you need to call it self.next(currentState).

Also, note, that you have defined incorrect initializer (aka. constructor). You have to use double underscores:

__init__(...

instead of:

_init_(...

otherwise it is just a method - not called while object creataion.

answered Sep 7, 2011 at 18:43

Michał Šrajer

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Comments

bcoughlan · Accepted Answer · 2011-09-07 18:39:02Z

0

Use self.next(currentState) instead, otherwise it's referring to the next() method of the iterator, not your class

answered Sep 7, 2011 at 18:39

bcoughlan

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Sean Vieira · Accepted Answer · 2011-09-07 18:42:43Z

0

The error means just what it says. When you use next(iterable), next tries to call the iterable's next method. However, when you do dir(0):

['__abs__',
 # ... snip ...
 '__xor__',
 'bit_length',
 'conjugate',
 'denominator',
 'imag',
 'numerator',
 'real']

As you can see, there is no next method on an integer.

If you are trying to call your own next method, then you need to use self.next not next. next is a builtin function that calls the next method of an iterator to let you do things like this:

 for something in my_iterator:
     print something

Try:

temp = self.next(currentState)

answered Sep 7, 2011 at 18:42

Sean Vieira

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