Replace regex value does not work when there is \d in string

Question

I have the below value as a plain text

`[a-zA-Z][a-zA-Z][a-zA-Z][a-zA-Z]sdsds\d\d`

I want to replace all [a-ZA-Z] with [C] and replace all \d with [N]. I tried to do this with the following code, but it does not work for \d.

value.replace(/\[a-zA-Z\]/g, '[C]').replace(/\\d/g, '[N]').replaceAll('\d', '[N]')

The final result must be:

[C][C][C][C]asass[N][N]

but it output

[C][C][C][C]s[N]s[N]s[N][N]

Note: I am getting this value from API and there is just one \ before d not \\.

Well, for starters. You're using regex as a search pattern when you shouldn't be. — John
– John, Commented Sep 1, 2022 at 2:56
.replaceAll('\\d', '[N]') You have to escape backslash in a string... — Nick
– Nick, Commented Sep 1, 2022 at 3:04
@Nick in this way, the output is [a-zA-Z][a-zA-Z][a-zA-Z][a-zA-Z]sdsdsdd which is incorrect — osman Rahimi
– osman Rahimi, Commented Sep 1, 2022 at 3:07
That's not how js strings work. Backslash on its own is an escape character, in order to have one in a string you have to escape it. Two backslashes will result in a single. stackoverflow.com/a/10042082/9360315 — AlienWithPizza
– AlienWithPizza, Commented Sep 1, 2022 at 3:16

Tim Biegeleisen · Accepted Answer · 2022-09-01 03:00:20Z

1

The issue here might actually be in your source string. A literal \d in a JavaScript string requires two backslashes. Other than this, your replacement logic is fine.

var input = "[a-zA-Z][a-zA-Z][a-zA-Z][a-zA-Z]sdsds\\d\\d";
var output = input.replace(/\[a-zA-Z\]/g, '[C]').replace(/\\d/g, '[N]');
console.log(output);

answered Sep 1, 2022 at 3:00

Tim Biegeleisen

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2 Comments

osman Rahimi Over a year ago

the problem is, in the input that I am getting from API , there is \d in the string not \\d

John Over a year ago

He doesn't need a regex search query to replace a non dynamic token with a literal string.

AlienWithPizza · Accepted Answer · 2022-09-01 03:25:47Z

1

You have some issues with \d. In the case of '\d' this will just result in 'd'. So maybe you wanted '\\d' as your starting string?

console.log('[a-zA-Z][a-zA-Z][a-zA-Z][a-zA-Z]sdsds\\d\\d'.replaceAll('[a-zA-Z]', '[C]').replaceAll('\\d', '[N]'));

edited Sep 1, 2022 at 3:25

answered Sep 1, 2022 at 3:02

AlienWithPizza

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3 Comments

John Over a year ago

You copied his typo so your snippet doesn't work.

osman Rahimi Over a year ago

In the string value, I have \d not \\d. your code won't work if you change \\d to \d

AlienWithPizza Over a year ago

'\\d' is you you get a backslash before a d. Go ahead and put '\d' in the console, it will just output d.

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