Is there a way to log a JS object except for one key in it? [duplicate]

Question

I have a JS object that i want to log to the console but one of its values is 5 million characters of a hashed image so im not really interessted in that. Is there a way to exclude this key from the console log / is there a short form for cloning the object, deleting the value and logging it?

Not a duplicate of "cloning object except for one key" btw

Given that the answer is “no, other than cloning the object except for that key”, is it in fact a duplicate of that? (You could serialize it to a string directly one way or another I guess, but you’ll lose all of the object inspection console features.) — Ry-
– Ry- ♦, Commented Sep 7, 2022 at 22:37
One would utilize the rest property within a destructuring assignment ... for instance like ... function logObjectWithoutKey(key, obj) { const { [ key ]: suppressed, ...rest } = obj; console.log(rest); } ... and then e.g ... logObjectWithoutKey('img', { foo: 'foo', bar: 'bar', baz: 'baz', img: 'a lot of data' }); ... or ... logObjectWithoutKey('baz', { foo: 'foo', bar: 'bar', baz: 'baz', img: 'a lot of data' }); — Peter Seliger
– Peter Seliger, Commented Sep 7, 2022 at 23:23

FortyGazelle700 · Accepted Answer · 2022-09-07 22:59:57Z

-2

One very easy way to do this is by using the spread operator [MDN Docs]

const yourObject = {id:"something",img: "5M-character-stuff"}
console.log({...yourObject, img: "short-img"});
// logs: {id:"something",img: "short-img"}

answered Sep 7, 2022 at 22:59

FortyGazelle700

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