How do I terminate a program in Python?

Question

This is my project description:

Write a program that displays the following menu:

1) Convert Fahrenheit to Celsius
2) Convert Celsius to Fahrenheit

Enter 1, 2, or 0 to exit:

In the case of options 1 and 2, the program should then prompt the user for the temperature, perform the conversion, and output the result. Then the program should re-display the menu. When option 0 is chosen, the program should exit.

Here is what I have so far:

a = raw_input("1) Convert Fahrenheit to Celsius \n2) Convert Celsius to Fahrenheit \nEnter 1, 2, or 0 to exit: ")

x = raw_input("Enter degree: ")

y = float((x - 32) / 1.8)

x = raw_input("Enter degree: ")

z = float((x + 32) * 1.8)

if a == 1:
    print(y)

if a == 2:
    print(z)

How can I terminate this program? Where else am I messing up?

I'd feel like a jerk if I didn't point out that your z equation should read: z = float((x / 1.8) + 32) — Vorticity
– Vorticity, Commented Sep 10, 2011 at 16:01

Mike DeSimone · Accepted Answer · 2011-09-10 04:11:18Z

1

Get rid of the second x = raw_input(... line. You don't need it.
Calculate y right before you print it, inside the if block. No point doing math the user didn't want.
Same for z: calculate it right before you need it.
Put this after the a = raw_input(... line:

Code:

if a == 0:
    import sys
    sys.exit(0)

answered Sep 10, 2011 at 4:11

Mike DeSimone

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1 Comment

glglgl Over a year ago

Just an addition: No one has mentionned the loop so far. Of course all that has to be in a while True: loop. And then you also can use break to leave that loop and terminate.

Jakob Bowyer · Accepted Answer · 2011-09-10 10:38:15Z

0

You need to:

convert a and x to int.

a = int(raw_input("1) Convert Fahrenheit to Celsius \n2) Convert Celsius to Fahrenheit \nEnter 1, 2, or 0 to exit: "))

x = int(raw_input("Enter degree: "))

Do the calculations inside if blocks.
Also, get rid of the second x = raw_input("Enter degree: ")
And as said in above answer, you can use the sys.exit(0)

edited Sep 10, 2011 at 10:38

Jakob Bowyer

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answered Sep 10, 2011 at 5:59

c0da

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