I only get one output that is multiply:6 but I want both outputs.
Why am I not getting a return value if I used return in class Add
class Add:
def result(self, x, y):
return f"add, a, b"
class multi(Add):
def result(self, a, b)
p=a*b
super().result (1, 2)
return f"multiply:{p}"
x=multi()
print(x.result(2, 3))
I want 2 outputs together
add: 3
multyply:6
you can return and print where you are calling super().result
class Add:
def result(self, x, y):
return f"add => {x} + {y} = {x+y}"
class multi(Add):
def result(self, a, b):
print(super().result (1, 2))
return f"multyply => {a} * {b} = {a*b}"
x=multi()
print(x.result(2, 3))
If you don't want to print inside the function multi:
class Add:
def result(self, x, y):
return f"add:{x+y}"
class multi(Add):
def result(self, a, b):
p=a*b
add = super().result (1, 2)
return add+"\n"+f"multiply:{p}"
x=multi()
print(x.result(2, 3))
Correct way:
class Add:
def result(self, x, y):
return f"add:{x + y}"
class Multi(Add):
def result(self, a, b):
add_result = super().result(a, b)
p = a * b
return f"{add_result}\nmultiply:{p}"
x = Multi()
print(x.result(2, 3))
Output:
add:5
multiply:6
Explanation:
You're calling the parent method (super().result()), but not capturing or printing its return value. In Python, when you override a method, the parent method doesn’t automatically run unless you explicitly call it — and even then, you need to use its return value (either store it or print it).
Hope that clears it up!
