PHP's json_decode() with this JSON string

Question

I have this JSON string:

 {
    "name": "test task1",
    "desc": "test desc1",
    "id": "1"
}{
    "name": "test task1aaaa",
    "desc": "test desc1",
    "id": "2"
}

But it looks like it's not correct (JSONLint tells me) so PHP's json_decode()can't decode it. There's any way to separate the two JSON arrays into two strings (or into how much string the arrays are) for making json_decode decode them?

karim79 · Accepted Answer · 2011-09-15 12:12:58Z

2

Assuming your intention is to have an array of two elements, your JSON should look like:

[
    {
        "name": "test task1",
        "desc": "test desc1",
        "id": "1"
    },{
        "name": "test task1aaaa",
        "desc": "test desc1",
        "id": "2"
    }
]

answered Sep 15, 2011 at 12:12

karim79

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1 Comment

pmerino Over a year ago

Thanks, just made it correct, was generating the array wrong :D

k102 · Accepted Answer · 2011-09-15 12:15:20Z

0

the most straightforward

$str = ' {
    "name": "test task1",
    "desc": "test desc1",
    "id": "1"
}{
    "name": "test task1aaaa",
    "desc": "test desc1",
    "id": "2"
}';

var_dump(json_decode('['.str_replace('}{','},{',$str).']'));

answered Sep 15, 2011 at 12:15

k102

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Comments

user680786 · Accepted Answer · 2011-09-15 12:18:30Z

0

<?php
$str='{
    "name": "test task1",
    "desc": "test desc1",
    "id": "1"
}{
    "name": "test task1aaaa",
    "desc": "test desc1",
    "id": "2"
}';

$arrays = explode("{", $str);
foreach($arrays as &$arr) $arr='{'.$arr;

//decode
foreach ($arrays as $arr) print_r(json_decode($arr,true));

answered Sep 15, 2011 at 12:18

user680786

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