I have a NSMutableArray, containing x different NSStrings (NSString but only numbers no letters). I would like to add up all of the values to return a single float, or int. I think I have to do this with a for loop, but i am very unfamiliar with for loops....
OK I have reached this point:
for (NSString *a in det)
{
float x = [a floatValue];
NSLog(@"%.2f",x);
}
And this returns all the values like this in ´NSLog`:
23.00
8.00
61.00
...
How could i just add them up now?
You can avoid looping and instead use the key value coding and obtain the total
NSMutableArray *arr = [NSMutableArray arrayWithObjects:@"1.1", @"2.2", @"3.1", nil];
NSNumber *sum = [arr valueForKeyPath:@"@sum.floatValue"];
Variable sum will be 6.4.
Try this:
float total = 0;
for(NSString *str in det)
{
total += [str floatValue];
}
Here is the code for a for-in if you want to save a bit of typing. It's preferable to use fast enumeration for these types of scenarios with data structures that support it.
float result = 0.0;
for(NSString *i in nsArray)
{
result += [i floatValue];
}
int result = 0;
for(int i=0;i<[array count];i++)
result += [[array objectAtIndex:i] intValue];
if you need to return a float simply define result as float and use floatValue instead of intValue
