PYTHON - grep command: wrong output, exit status 2

Question

I trying to find a Pattern in specific large files (GB) in subfolders

I am runnging Python code.

tried....

FILE_PATH=/folder1/FILE.txt - OK, absolute path

with open (FILE_PATH, "r") as FILE:
  for index, x in enumerate(FILE):
    if re.findall(".*TEXT.*", x):
      ...takes too much time...

another way

in Bash from terminal:

grep -a 'TEXT' /folder1/FILE.txt - output OK as desired

Python code:

FILE_PATH=/folder1/FILE.txt - OK, absolute path

STATUS=(subprocess.check_output("grep -a \'TEXT\' " + str(FILE_PATH.encode()), shell=True)).rstrip('\n')

I get this output in terminal
...: Command 'grep -a 'TEXT' b'/folder1/FILE.txt'' returned non-zero status 2

Any advice, please?

How to run Bash GREP command in Python on both binary/text file with variables (File path) ang store grep output into Variable in Python

Cow · Accepted Answer · 2022-11-10 10:04:24Z

1

You could try to use os.popen(), which should mimic and return the result you see when using the bash command:

import os
FILE_PATH = "/folder1/FILE.txt"
results = os.popen(f"grep -a 'TEXT' {FILE_PATH}").read()
print(results)

answered Nov 10, 2022 at 10:04

Cow

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2 Comments

Scripter Over a year ago

what does the ...f... stands for? - os.popen(f"grep..... I can not find it in manual

Cow Over a year ago

@Scripter It's an f-string, you can look it up. :)

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