python vlc, how to change a radio channel when button is pressed?

Question

im trying to build a program (using pysimplegui) which contains a few buttons (play, stop, pause, next, previous) as you can see. and when i press "next" its stopping for some time and then the same music continues (i dont press "previous" because i know that will cause problem 0 - 1 = -1). `

global n
n = 0
media_player = vlc.MediaPlayer() 
url = ['http://cast.radiogroup.com.ua:8000/avtoradio', 'http://listen.rpfm.ru:9000/premium128', 'http://cast.loungefm.com.ua/terrace128']
media_player.set_mrl(url[n])

if event == 'play':
  media_player.play()

if event == 'stop': 
  media_player.stop()
     
if event == 'pause':
  media_player.pause()

if event == 'next':
  global n
  n + 1
  media_player.set_mrl(url[n])
  media_player.play()
        
if event == 'previous':
  n - 1
  media_player.set_mrl(url[n])
  media_player.play()

`

ive tried to google this problem
i didnt find the documentation
im trying to run it in a bit different way, using `

import vlc
playlist_url = ['http://cast.radiogroup.com.ua:8000/avtoradio', 'http://listen.rpfm.ru:9000/premium128', 'http://cast.loungefm.com.ua/terrace128']
n = int(input())
instance = vlc.Instance('--intf dummy')
player = instance.media_list_player_new() 
media = instance.media_list_new(playlist_url[n])
player.set_media_list(media)  
player.play()

` but it returns [0000027223bc32e0] filesystem stream error: cannot open file C:\Users\dadva\Desktop\Project\h (No such file or directory) [0000027223ba3220] main input error: Your input can't be opened [0000027223ba3220] main input error: VLC is unable to open the MRL 'file:///C:/Users/dadva/Desktop/Project/h'. Check the log for details.

In your first code: n - 1 and n + 1 don't do anything, the result of the calculation is immediately discarded. You probably want n = n - 1 and n = n + 1. So when you hit "next", it stops playing, re-queries the (same) URL, and plays again. This is probably the short delay you notice. — Robert
– Robert, Commented Nov 10, 2022 at 16:48

Jason Yang · Accepted Answer · 2022-11-11 01:57:00Z

0

Demo Code

import vlc
import PySimpleGUI as sg

playlist_url = [
    'http://cast.radiogroup.com.ua:8000/avtoradio',
    'http://listen.rpfm.ru:9000/premium128',
    'http://cast.loungefm.com.ua/terrace128',
]
n, m = 0, len(playlist_url)

player = vlc.MediaPlayer()
player.set_mrl(playlist_url[n])
player.play()

layout = [[sg.Button('PREV'), sg.Button('NEXT')]]
window = sg.Window('VLC Player', layout)

while True:

    event, values = window.read()

    if event == sg.WIN_CLOSED:
        break
    elif event in ('PREV', 'NEXT'):
        n = (n+1) % m if event == 'NEXT' else (n-1) % m
        player.set_mrl(playlist_url[n])
        player.play()

player.stop()
window.close()

answered Nov 11, 2022 at 1:57

Jason Yang

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