Bash Case --> function ---> case

Question

I tried a lot of things, but this design does not want to work in any way

#!/bin/bash

trap 'echo "# $BASH_COMMAND";read' DEBUG


test () {  
    case "$2" in
    3) echo "3" 
       ;;
    4) echo "4" 
       ;;
    esac
}

while :
do
case "$1" in 

    1) echo "1" ;;
    2) test;;

esac
done

if i use case in case it/s work, and when i use read to $2 it work, but i want to work with keys from command line

You’re calling test (not a good function name, BTW) without any arguments. $2 within test is not set. — Biffen
– Biffen, Commented Nov 18, 2022 at 10:30
Or to state it explicitly: Outside of a function $1, $2, ... will be the arguments your script was called with (unless re-set using set), but inside of a function those will have the values of the arguments to that function and you called test without any arguments. — Joachim Sauer
– Joachim Sauer, Commented Nov 18, 2022 at 10:35
tnx and sorry for my simpl mistake, now everything works as it should — Федор Ермолаев
– Федор Ермолаев, Commented Nov 18, 2022 at 10:50

Biffen · Accepted Answer · 2022-11-18 11:10:28Z

1

test () {  
    case "$1" in

    3) echo "3"
       exit 0 
       ;;
    4) echo "4"
       exit 0 
       ;;
    esac
}

while :
do
case "$1" in 

    1) echo "1" ;;
    2) test $2;;

esac
done

edited Nov 18, 2022 at 11:10

Biffen

6,3786 gold badges32 silver badges38 bronze badges

answered Nov 18, 2022 at 10:51

Федор Ермолаев

112 bronze badges

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2 Comments

user1934428 Over a year ago

But of course it is a terrible idea to name a function like a standard utility. Even if the OP did it - we shouldn't repeat poor design choices in an answer. I suggest that you change test into, i.e., test4711.

Федор Ермолаев Over a year ago

i used "test" just for test ))

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