Call OpenAI API with Python requests is missing a model parameter

Question

I'm trying to call OpenAI API from Python. I know they have their own openai package, but I want to use a generic solution. I chose the requests package for its flexibility. Here is my call

>>> headers = {"Authorization": "Bearer xxx"}
>>> url = 'https://api.openai.com/v1/completions'
>>> data = {'model': 'text-davinci-002', 'prompt': 'Once upon a time'}
>>> requests.get(url, headers=headers, data=data).content
...  "error": {\n        "message": "you must provide a model parameter"

The header contains the API token. It's correct, I tried it. I also tried to pass the same dictionary as json, as data but as a json string. Always the same error message. Any idea how to make the call?

Update:

>>> requests.get(url, headers=headers, json=data).content
>>> requests.get(url, headers=headers, json=json.dumps(data)).content
>>> requests.get(url, headers=headers, data=json.dumps(data)).content
>>> requests.get(url, headers=headers, data=json.dumps(data).encode()).content

These all return the same error. I tried to add 'Content-Type': 'application/json' to the headers too.

update2: It works for the completion endpoint with POST, but not for the edit endpoint.

>>> completion_url =  "https://api.openai.com/v1/completions"
>>> completion_data = {'model': 'text-davinci-002', 'prompt': 'Once upon a time'}
>>> requests.post(completion_url, headers=headers, json=completion_data).json()
... # it works
>>> edit_url =  "https://api.openai.com/v1/edits"
>>> completion_data = {'model': 'text-davinci-002', 'input': 'Once upon a time', 'instruction': 'Continue'}
>>> requests.get(edit_url, headers=headers, json=edit_data).json()['error']['message']
'you must provide a model parameter'
>>> requests.post(edit_url, headers=headers, json=edit_data).json()['error']['message']
'Invalid URL (POST /v1/edits)'

Martijn Pieters · Accepted Answer · 2022-11-27 20:27:21Z

The API expects a JSON request body,not a form-encoded request. And, you need to use the requests.post() method to send the right HTTP method.

Use the json argument, not the data argument, and the right method:

requests.post(url, headers=headers, json=data)

See the Create completion section of the OpenAI documentation, where the curl source code sample posts JSON:

curl https://api.openai.com/v1/completions \
  -H 'Content-Type: application/json' \
  -H 'Authorization: Bearer YOUR_API_KEY' \
  -d '{
  "model": "text-davinci-002",
  "prompt": "Say this is a test",
  "max_tokens": 6,
  "temperature": 0
}'

as well as the More complicated POST requests section of the documentation:

Typically, you want to send some form-encoded data — much like an HTML form. To do this, simply pass a dictionary to the data argument. Your dictionary of data will automatically be form-encoded when the request is made[.]

[...]

There are times that you may want to send data that is not form-encoded.

[...].

If you need [the application/json header] set and you don’t want to encode the dict yourself, you can also pass it directly using the json parameter (added in version 2.4.2) and it will be encoded automatically[.]

(Bold emphasis mine, slightly edited for clarity).

Demo:

>>> import requests
>>> key = "<APIKEY>"
>>> headers = {"Authorization": f"Bearer {key}"}
>>> data = {'model': 'text-davinci-002', 'prompt': 'Once upon a time'}
>>> requests.post(url, headers=headers, json=data).json()
{'id': 'cmpl-6HIPWd1eDo6veh3FkTRsv9aJyezBv', 'object': 'text_completion', 'created': 1669580366, 'model': 'text-davinci-002', 'choices': [{'text': ' there was a castle up in space. In this castle there was a queen who', 'index': 0, 'logprobs': None, 'finish_reason': 'length'}], 'usage': {'prompt_tokens': 4, 'completion_tokens': 16, 'total_tokens': 20}}

The openai Python library uses the requests library under the hood but takes care of details like how to send HTTP requests correctly for you.

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