let's say i have 2 files: a.php and b.php
a.php
$value = "test";
i would like to update the $value by using b.php. i want to run b.php and change a.php like that:
$value = "changed";
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2 Answers
here is the code to open a php file using php :
$file = "/home/dir/file.php";
$fs = fopen( $file, "a+" ) or die("error when opening the file");
while (!feof($fs)) {
$contents .= fgets($fs, 1024);
}
fclose($fs);
now you can take the $contents and modify it to however you would like and then save it. here is how you can save it :
$fs = fopen( $_POST["file"], "a+" ) or die("error when opening the file");
fwrite($fs, $updatedContents);
fclose();
$updatedContents is the updated content
4 Comments
ahoura
thanks, I would appreciate it you could choose my answer and/or vote up if it helped you solve your problem
Ignacio Vazquez-Abrams
Self-modifying code has its own set of problems, and unless you're ready to solve them you should avoid it.
ahoura
I completely agree with Ignacio, however the OP asked to self-modify the code and the code above does that, but you are right, its better if it can be avoided.
Blowsie
what if the file is say, a config-file?
No you don't. Put the value in an external source, either a flat file or a database, and read in the value in a.php.
answered Sep 17, 2011 at 23:18
Ignacio Vazquez-Abrams
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