Bash recursive program

Question

Here is my function so far:

function create {
        a=$3 
        while [  $a -lt $secondnum ]
        do
                echo "mkdir $1/$a"
                if [ $2 -lt $firstnum ] 
                then
                        sum=$(($2+1))
                        d=$(($a))
                        create "$1/$d" $sum 0
                fi 
                a=$(($a+1))
        done    
}

Its echoing

mkdir hw1/0
mkdir hw1/0/0
mkdir hw1/0/0/0
mkdir hw1/0/0/1
mkdir hw1/0/0/2

It's supposed to create a whole directory, not just one branch. (e.g. hw///* branch aswell) This is a homework project so I need to use bash.

What is the output you expect?

Felix Kling
– Felix Kling

2011-09-19 13:37:33 +00:00
Commented Sep 19, 2011 at 13:37 — Felix Kling
– Felix Kling, Commented Sep 19, 2011 at 13:37

Matt K · Accepted Answer · 2011-09-19 13:38:53Z

1

I believe bash variables are global by default. If you want a function-local variable, you need to use the local keyword.

$ help local
local: local [option] name[=value] ...
Define local variables.

Create a local variable called NAME, and give it VALUE.  OPTION can
be any option accepted by 'declare'.

Local variables can only be used within a function; they are visible
only to the function where they are defined and its children.

Exit Status:
Returns success unless an invalid option is supplied, an error occurs,
or the shell is not executing a function.

answered Sep 19, 2011 at 13:38

Matt K

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