I have a string like this:
let s = '10p6s23'
I'd like to split it in such a way that I get the numbers and the letters in an array, so ideally I'd get this:
[10,'p',6,'s',23]
The ultimate goal is to build a add/subtract calculator where p = + and s = -. So the string above would resolve to 10 + 6 - 23 = -7.
Split string into array on first non-numeric character in javascript
This worked well, except it only split on the first char, not all chars.
const regexp = /(\d+|[a-z]+)/g;
const str = '10p6s23';
const array = [...str.match(regexp)];
console.log(...array);
let replaced = array.map(item => {
switch(item) {
case 'p':
return '+';
case 's':
return '-';
default:
return item;
}
}).join('');
console.log(eval(replaced));
eval(s.split('p').join('+').split('s').join('-'))you can use match function here.
'10p6s23'.match(/[a-zA-Z]+|[0-9]+/g)
// /[a-zA-Z]+|[0-9]+/g this is the regular expression for numbers or letters
One way to do it is by using a Regular Expression
let s = '10p6s23'
const numbers = [...s.matchAll(/\d+/g)].map((num) => parseInt(num));
const operators = [...s.matchAll(/\D+/g)];
console.log(numbers);
console.log(operators);And work from here with the rest of the logic
You could split on:
(?<=[a-z])\d+ or(?<=\d)[a-z]+Afterwards, you will have the filter on non-empty values.
const regexp = /((?<=[a-z])\d+|(?<=\d)[a-z]+)/ig;
const str = '10p6s23';
const array = str.split(regexp).filter(x => x.length);
console.log(...array);Here is an iterative replacement solution:
const compute = (input) => {
let
count = input.match(/[ps]/g).length,
result = input;
while (count --> 0) {
result = result.replace(
/(\d+)([ps])(\d+)/,
(_, left, op, right) => {
switch (op) {
case 'p': return parseInt(left, 10) + parseInt(right, 10);
case 's': return parseInt(left, 10) - parseInt(right, 10);
}
}
);
}
return result;
};
console.log(compute('10p6s23'));
eval?eval(s.split('p').join('+').split('s').join('-'))