powershell upload blob to azure blob storage set content type

Question

I am making a ReST api call and uploading the JSON payload to azure blob storage using the below powershell.

PoSh:

        $Params = @{"URI" = 'https://myapiexample.com/api/data/'}
         
        $Result = Invoke-RestMethod @Params | ConvertTo-Json
        
        $context=New-AzStorageContext -StorageAccountName "mystorage" -StorageAccountKey ""
        
        $container=Get-AzStorageContainer -Name "input" -Context $context
        
        $content = [system.Text.Encoding]::UTF8.GetBytes($Result)
        $blobpath = "azblob/mydata.json"
        
        $container.CloudBlobContainer.GetBlockBlobReference($blobpath).UploadFromByteArray($content,0,$content.Length)
    
    $container.CloudBlobContainer.GetBlockBlobReference($blobpath).Properties.ContentType = "application/json"

$container.CloudBlobContainer.GetBlockBlobReference($blobpath).SetProperties()

I notice that when the blob is stored in azure blob storage the content-type is application/octet-stream whereas I would want it to be application/json. The code I use is not working as expected.

Isn't the result you're getting from Invoke-RestMethod already in JSON format? If so, remove the pipe to ConvertTo-Json — Theo
– Theo, Commented Dec 8, 2022 at 14:41
@Theo I tried that too but for some reason not being able to set content-type to application/json — paone
– paone, Commented Dec 8, 2022 at 17:55

SwethaKandikonda · Accepted Answer · 2022-12-13 08:56:23Z

1

After reproducing from my end, I could able to achieve your requirement using Set-AzStorageBlobContent. Below is the complete code that is working for me that sets the content type of the blob.

$url = "<YOUR_URL>"
$dest = "samplex.json"
Invoke-WebRequest -Uri $url -OutFile $dest
$context = New-AzStorageContext -StorageAccountName "<YOUR_ACCOUNT_NAME>" -StorageAccountKey "<YOUR_ACCOUNT_KEY>"
Set-AzStorageBlobContent -Context $context -Container "containers" -Blob "mydata.json" -File $dest -Properties @{"ContentType" = "application/json"};

RESULTS:

enter image description here

answered Dec 13, 2022 at 8:56

SwethaKandikonda

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1 Comment

paone Over a year ago

I'm reading the data into the variable $Result. How do I use this with -File parameter. I guess in your example the -OutFile set to a local drive. But, in my case I would need to read the file from a variable.

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