I have two arrays. I want to compare them and make a new array out of it with matched values but I want to keep duplicate values as well.
Like:
let array1 = [1, 3, 3, 3]
let array2 = [{id:1}, {id:2},{id:3}]
array1 = array1.filter(e1 => array2.some(e2 => e2.id === e1))
array2 = array2.filter(e1 => array1.some(e2 => e2 === e1.id))
output:
array2 = [{id:1}, {id:3}]
But I want to get the duplicate as well.
Desired output
array2=[{id:1}, {id:3}, {id:3}, {id:3}] //as array1 has 3 multiple time
We can use Array.filter() and Array.map() to change data of array1,then assign it to array2
let array1 = [1, 3, 3, 3]
let array2 = [{id:1}, {id:2},{id:3}]
array2 = array1.filter(e1 => array2.some(e2 => e2.id === e1)).map(e => ({'id':e}))
console.log(array2)Update:without assign value from array1 to array2
let array1 = [1, 3, 3, 3]
let array2 = [{id:1}, {id:2},{id:3}]
array1 = array1.filter(e1 => array2.some(e2 => e2.id === e1))
array2 = array2.filter(e1 => array1.some(e2 => e2 === e1.id))
array1 = array1.reduce((a,v) =>{
a[v] = a[v]??0
a[v] += 1
return a
},{})
array2 = array2.reduce((a,v) =>{
let cnt = array1[v.id]
for(let i=0;i<cnt;i++){
a.push({...v})
}
return a
},[])
console.log(array2)