How to format numbers without rounding in Python?

Question

I was searching online but could find if this is posible. I have a number, let say 1234.5963657 and I know that with f-string I can do this f"{number:,.2f}" to obtain 1,234.60.

The thing is that the number has been rounded, and I don't want that, I would like to obtain: 1,234.59. My question is if there's a way to do this as simple as the f-string.

If not, I would have to truncate it or do something like this:

number = 1234.5963657
int_part, dec_part = str(number).split('.')
new_number = f"{int_part}.{dec_part[:2]}" # 1234.59

Hope my question is clear. Thanks

Does this answer your question? Python setting Decimal Place range without rounding? — mkrieger1
– mkrieger1, Commented Dec 9, 2022 at 16:11
I read it before creating this post, but I find my way with strings "quicker" — antusystem
– antusystem, Commented Dec 9, 2022 at 16:13
Yes, I would like to truncate the number, but not like the math.trunc() function which only returns the integer part of the number, because I need also 2 decimals. — antusystem
– antusystem, Commented Dec 9, 2022 at 16:21
Does this answer your question? Truncate to three decimals in Python — Gert Arnold
– Gert Arnold, Commented Dec 9, 2022 at 18:17

wwii · Accepted Answer · 2022-12-09 17:35:42Z

1

Add one more digit of precision then use a slice to exclude the unwanted digit.

f"{number:,.3f}"[:-1]

answered Dec 9, 2022 at 17:35

wwii

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1 Comment

antusystem Over a year ago

Ohhh, nice, I think this could be the best way of doing it, let me try it

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