List comprehension with boolean (Python)

Question

How to present this code as a list comprehension:

def all_targets_hit(attempts: list) -> bool:

    for ls in range(len(attempts)):
        if not any(attempts[ls]):
            return False
    return True

attempts =([
            [True, False, False],
            [False, False, True],
            [False, False, False, False],
        ])

#Expected: False

That code is not right. It's only going to look at the first row, because you always return. ls will never get past 0. What do you want this to do? — Tim Roberts
– Tim Roberts, Commented Dec 15, 2022 at 19:21
@Tim Roberts Sorry, indentation error, corrected. I just need a solution in one row — avkpol
– avkpol, Commented Dec 15, 2022 at 19:34

Maurice Meyer · Accepted Answer · 2022-12-15 19:59:05Z

1

You could combine all with any:

def all_targets_hit(attempts: list) -> bool:
    return all([any(sublist) for sublist in attempts])

attempts =([
            [True, False, False],
            [False, False, True],
            [False, False, False, False],
        ]) 

all_targets_hit(attempts)

edited Dec 15, 2022 at 19:59

answered Dec 15, 2022 at 19:37

Maurice Meyer

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3 Comments

avkpol Over a year ago

Thanks a lot! But I need smth like/ return all(any(ls) for ls in attempt for attempt in attempts) / as list comprehension. But it seems doesn`t work

avkpol Over a year ago

Thanks for your reply! But I need smth like return all(any(ls) for ls in attempt for attempt in attempts) as list comprehension. But it doesn`t work with one list of attempts: 'bool' object is not iterable

avkpol Over a year ago

Now all is ok, thanks again!

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