Group array of items using jQuery

Question

How can I group items inside of a loop using jQuery?

I have these items like these in each loop iteration:

['ab', 'sd']
['ab', 'dc']
['ab', 'ca']
['bc', 'ds']
['bc', 'ea']

And I need to have an output like this:

{'ab':[sd,dc,ca],'bc':[ds,ea]}

I tried to filter them, but I couldn't achieve this.

This is not list that exact things this is loop array each array inside loop that loop how to make group ['ab', 'sd'], ['ab', 'dc'],['ab', 'ca'], ['bc', 'ds'], ['bc', 'ea'], ['bc','ea',ta] output {'ab':[sd,dc,ca],'bc':[ds]{'ea',[ta]} like this — Methababu
– Methababu, Commented Dec 16, 2022 at 13:02
Please clarify your specific problem or provide additional details to highlight exactly what you need. As it's currently written, it's hard to tell exactly what you're asking. — Community
– Community Bot, Commented Dec 19, 2022 at 21:36

Carsten Løvbo Andersen · Accepted Answer · 2022-12-16 13:25:55Z

0

1 way you can do it is like this:

$.each(input, function(i, n) {
  var keyW = n[0];
  if (output[keyW] == undefined) {
    output[keyW] = [];
  }

  if ($.inArray(n[1], output[keyW]) === -1) {
    output[keyW].push(n[1])
  }

})

Demo

var input = [
  ['ab', 'sd'],
  ['ab', 'dc'],
  ['ab', 'ca'],
  ['bc', 'ds'],
  ['bc', 'ea'],
  ['bc', 'ea']
];


var output = {};


$.each(input, function(i, n) {
  var keyW = n[0];
  if (output[keyW] == undefined) {
    output[keyW] = [];
  }

  if ($.inArray(n[1], output[keyW]) === -1) {
    output[keyW].push(n[1])
  }

})


console.log(output)

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

answered Dec 16, 2022 at 13:25

Carsten Løvbo Andersen

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2 Comments

Methababu Over a year ago

This is works only two array only what about third one when ever if third value also is same then create inner child array example : ['VSB', 'Agent'] ['VSB', 'Agent Procedure'] ['VSB', 'Anti-Malware'] ['TraverseOut', 'Devices'] ['TraverseOut', 'Signatures'] ['BS', 'HR'] ['BS', 'Finance'] ['AnuuthAnvil', 'On-Demand', '2FA'] ['AuthAnvil', 'On-Premise', '2fa'] ['Unigma', 'Monitor'] ['Unigma', 'Report'] ['365 Command', 'Monitor'] ['365 Command', 'Report']

Carsten Løvbo Andersen Over a year ago

@Methababu 3 array was not part of your original question.

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