How adding 0x to output values to be as hexadecimal input value

Question

I have output

New_MS= 102311144

I need to make this value as input by read each two number and add 0x to be hexadecimal, if the last number is just one number then should added 0 to end. As like in below

New_MS= (0x10, 0x23, 0x11, 0x14, 0x40)

Any idea how to do this

PandaBlue · Accepted Answer · 2022-12-23 16:05:45Z

2

Transform to string, then split every second character (see here: Split string every nth character? ).

Then left justify your parts:

New_MS = 102311144

str_ms = str(New_MS)

n = 2
split_str_ms = [str_ms[i : i + n] for i in range(0, len(str_ms), n)]

ms_txt_list = [f"0x{d.ljust(2, '0')}" for d in split_str_ms]
print(f"({','.join(ms_txt_list)})")

edited Dec 23, 2022 at 16:05

answered Dec 23, 2022 at 15:43

PandaBlue

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1 Comment

Mohammed Farttoos Over a year ago

Thanks for answer, its near from what I need, but output is ['0x10', '0x23', '0x11', '0x14', '0x40'], I need it New_MS= (0x10, 0x23, 0x11, 0x14, 0x40) exactly same Brackets () and no comma ''

Bart Friederichs · Accepted Answer · 2022-12-23 15:45:36Z

0

I know we shouldn't provide answers without having OP show his work, but it's almost christmas. Here is my shot:

New_MS= 102311144

s = f"{New_MS}"
start = 0
t = ()
while s[start:start+2]:
    chunk = s[start:start+2]
    if len(chunk) == 1:
        chunk += "0"

    t += (int(chunk, 16),)

    start += 2

print(t)

answered Dec 23, 2022 at 15:45

Bart Friederichs

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2 Comments

Mohammed Farttoos Over a year ago

OK it good but the output is (16, 35, 17, 20, 64) not (0x10, 0x23, 0x11, 0x14, 0x40) what I asked for

Bart Friederichs Over a year ago

Your request shows not a tuple of strings, but a tuple of integers. These values are the same.

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