C# Bitwise Operator With Ints

Question

What does this expression actually mean??

Note - the x and y vars are just sample values.

int x = 3; 
int y = 1; 

if ((x & y) !=0)

I inherited a codebase and am not up to speed on bitwise operators. I have read up, but am still missing something. Help!

Dan J · Accepted Answer · 2011-09-20 20:47:40Z

8

It's comparing the bits in each value. It returns any bits that are set in both numbers.

In your example:

    3:  0011
    1:  0001

3 & 1:  0001

edited Sep 20, 2011 at 20:47

Dan J

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answered Sep 20, 2011 at 20:36

Joe

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BrokenGlass · Accepted Answer · 2011-09-20 20:36:18Z

2

This checks whether x and y both have at least one common bit set. In the case of your example this would be the true.

answered Sep 20, 2011 at 20:36

BrokenGlass

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Dan J · Accepted Answer · 2011-09-20 20:47:13Z

1

if ((x & y) != 0)

This would typically be used to determine whether the value x has a specific bit-flag (y) set. The AND operator returns an integer with only those bits set that are set in both operands.

edited Sep 20, 2011 at 20:47

Dan J

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answered Sep 20, 2011 at 20:35

driis

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