Combine javascript objects from an array that contain almost similar key

Question

I have an array that contains objects. The array looks like this:

[
    {
        "number": "10a",
        "person": "Velvet"
    },
    {
        "number": "10b",
        "person": "Edna"
    },
    {
        "number": "11a",
        "person": "Shionne"
    },
    {
        "number": "11b",
        "person": "Aifread"
    },

]

I want to combine objects that have identical number property. For example, the first two objects have property number: "10a", and number: "10b". I want these to be combined such that the output becomes:

{
    "10": {
       "person": ["Velvet", "Edna"]
    },
    "11": {
       "person": ["Shionne", "Aifread"]
    }
}

I am not sure how to do it as it seems too complicated for me. I also looked over stackoverflow but can't seem to find a similar problem, hence, my post. Thanks for the help!

Is number has fixed length 3? If not ,it will be difficult to define similar — flyingfox
– flyingfox, Commented Jan 13, 2023 at 11:34
Can we reopen the problem? The suggested answer doesnt answer my probem. Thanks — Seven
– Seven, Commented Jan 13, 2023 at 11:35
Ther are plenty of articles and questions about array transformations. Good articles is here medium.com/@jasminegump/… What is your number format? always any number and one letter? — Jan Pfeifer
– Jan Pfeifer, Commented Jan 13, 2023 at 11:35

Rumpelstinsk · Accepted Answer · 2023-01-13 11:49:29Z

1

I'll assume that the normalization for number is just to remove non numeric characters. If so, you can just iterate over the original array and process each element:

var original = [
    {
        "number": "10a",
        "person": "Velvet"
    },
    {
        "number": "10b",
        "person": "Edna"
    },
    {
        "number": "11a",
        "person": "Shionne"
    },
    {
        "number": "11b",
        "person": "Aifread"
    },
];

const merged = {}
    
        original.forEach(item => {
            var normalizedKey = item.number.replaceAll( /\D/g, "" )
            if(!merged[normalizedKey]) merged[normalizedKey] = { person: []}
            merged[normalizedKey].person.push(item.person)
        })
        
        console.log({merged})

answered Jan 13, 2023 at 11:49

Rumpelstinsk

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1 Comment

Seven Over a year ago

I knew there was a way to loop only once but I couldn't figure it out! This was the answer I am looking for! Thank you very much!

Jan Pfeifer · Accepted Answer · 2023-01-13 11:49:48Z

0

Parse number. Add object if missing and append name:

const result = {};
arr.forEach(o => {
    const nr = o.number.slice(0,2);
    result[nr] = result[nr] || {person:[]};
    result[nr].person.push(o.person);
});

console.log(result);

answered Jan 13, 2023 at 11:49

Jan Pfeifer

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