Use first generic type parameter for second and third parameter in typescript without having to put all parameters [duplicate]

I have the following types

type CommonDic<Dic> = {
  [I in keyof Dic]: {
    [W in keyof Dic[I]]: string;
  };
};

type MyDic = {
  a: {
    apple: string;
    ant: string;
  };
  b: {
    banana: string;
    bear: string;
  };
};

Problem

const getWord = <D extends CommonDic<D>, T extends keyof D, W extends keyof D[T]>(key: T, word: W) => {
  return {
    key,
    word,
  };
};

const word1 = getWord<MyDic>("a", "apple");
// error TS2558: Expected 3 type arguments, but got 1.

The code below works but any way to do this without currying?

const getWord2 =
  <D extends CommonDic<D>>() =>
  <T extends keyof D, W extends keyof D[T]>(key: T, word: W) => {
    return {
      key,
      word,
    };
  };

const word2 = getWord2<MyDic>()("a", "apple"); // works

I've tried default type parameter but wasn't successful. Thanks!