I am trying to create a logout feature which when clicked from the below (example) redirects to the necessary page.
Example:
- If anybody clicks logout with website beginning with aaa.io/user -> go to aaa.io/login.
- If anybody clicks logout with website beginning with aaa.io/dev/{id} -> go to aaa.io/home/{id}
How to create two logout feature which will redirect to two seperate pages? I have tried with first example and works fine.I heard we can do it using Symfony firewall but unable to get it.
#security.yaml
security:
enable_authenticator_manager: true
# https://symfony.com/doc/current/security.html#registering-the-user-hashing-passwords
password_hashers:
Symfony\Component\Security\Core\User\PasswordAuthenticatedUserInterface: 'auto'
App\Entity\Dimitry:
algorithm: auto
providers:
app_user_provider:
entity:
class: App\Entity\Dimitry
property: email
firewalls:
dev:
pattern: ^/(_(profiler|wdt)|css|images|js)/
security: false
main:
lazy: true
provider: app_user_provider
custom_authenticator: App\Security\LoginAuthenticator
logout:
path: app_logout
target: app_login
//Security Controller
#[Route(path: '/login', name: 'app_login')]
public function login(AuthenticationUtils $authenticationUtils): Response
{
if ($this->getUser()) {
return $this->redirectToRoute('app_home');
}
// get the login error if there is one
$error = $authenticationUtils->getLastAuthenticationError();
// last username entered by the user
$lastUsername = $authenticationUtils->getLastUsername();
return $this->render('security/login.html.twig', ['last_username' => $lastUsername, 'error' => $error]);
}
#[Route(path: '/logout', name: 'app_logout')]
public function logout()
{
return $this->redirectToRoute('app_login');
//throw new \LogicException('This method can be blank - it will be intercepted by the logout key on your firewall.');
}