Regex to replace the character after pattern match

Question

For my Java app, i have a string that looks like:

value1: *sample", test
test: "test"
newtest: *newtest"

I need to match the character " when the string starts with *.
Tried the regex: "(?!.*") But this selected all the " in the input.
Was planning to replaceAll(regex, "") to remove the character.

Desired Output:

value1: *sample, test
test: "test"
newtest: *newtest

How do i get this output?

This worked, Thanks. I can see that you are matching the word starting with * and ending with ", how did the " get replaced? — Vishnu Kumar
– Vishnu Kumar, Commented Jan 20, 2023 at 17:40

Wiktor Stribiżew · Accepted Answer · 2023-01-20 18:48:31Z

1

You can use

.replaceAll("(\\*\\w+)\"", "$1")

Details:

(\*\w+) - Group 1 ($1 refers to the text captured in this group)
" - a " char (just matched, not captured, so eventually removed).

answered Jan 20, 2023 at 18:48

Wiktor Stribiżew

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