Return multiple values from a method

Question

Hi guys i'm having a problem regarding returning multiple values from a method. I'm using 'out' to return other value from a method, here the snippet:

public DataTable ValidateUser(string username, string password, out int result)
{
    try
    {
        //Calls the Data Layer (Base Class)
        if (objDL != null)
        {
            int intRet = 0;
            sqlDT = objDL.ValidateUser(username, password, out intRet);
        }
    }
    catch (Exception ex)
    {
        ErrorHandler.Handle(ex);
        OnRaiseErrorOccuredEvent(this, new ErrorEventArgs(ex));
    }
    return sqlDT;
}

then when i compile having a error like this:

"The out parameter 'return' must be assigned to before control leaves the current method"

Anyone guys can help me solve this.

What is sqlDT? Where is it defined?

zerkms
– zerkms

2011-09-23 02:49:47 +00:00
Commented Sep 23, 2011 at 2:49 — zerkms
– zerkms, Commented Sep 23, 2011 at 2:49

MPelletier · Accepted Answer · 2011-09-23 02:50:16Z

2

That means in all possibilities (inside and outside the if, in the catch), your result variable must be assigned.

The best approach would be to give it a default value at the start of the function:

public DataTable ValidateUser(string username, string password, out int result)
{
    result = 0;
    try
    {
        //Calls the Data Layer (Base Class)
    if (objDL != null)
    {
        int intRet = 0;
        sqlDT = objDL.ValidateUser(username, password, out intRet);
        result = intRet;
    }
//....

answered Sep 23, 2011 at 2:50

MPelletier

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1 Comment

Rob Over a year ago

thanks it works.. actually I put result = intRet awhile a go but same problem now the work around i made i initialize the value of result to zero first result = 0

BrokenGlass · Accepted Answer · 2011-09-23 02:49:02Z

1

The parameter result of your method is marked as out. Parameters marked with out must be assigned within your method, i.e

result = 5;

This is enforced so callers of your method have the guarantee that the parameter that is passed with out is always set once your method finishes.

answered Sep 23, 2011 at 2:49

BrokenGlass

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Comments

acqu13sce · Accepted Answer · 2011-09-23 02:55:01Z

1

You're not setting the result variable in the method.

I'm guessing you want to add an extra line such as

result = intRet;

edited Sep 23, 2011 at 2:55

answered Sep 23, 2011 at 2:49

acqu13sce

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