Why the url first parameter is not being considered in Javascript?

Question

const url = new URLSearchParams('https://example.com?q1=1&q2=2');
console.log(url.has('q3')) // returns false as expected
console.log(url.has('q2')) // returns true as expected
console.log(url.has('q1')) // returns false as NOT expected

Why it happens?

Does this answer your question? URLSearchParams does not return the same string as found in a URL's parameters — 0stone0
– 0stone0, Commented Jan 30, 2023 at 10:47

Quentin · Accepted Answer · 2023-01-30 10:37:26Z

5

The URLSearchParams constructor, if passed a string, expects that string to be a query string and not a complete URL.

q1 doesn't appear because your first parameter is https://example.com?q1.

const url = new URLSearchParams('https://example.com?q1=1&q2=2');
console.log([...url.entries()]);

Use the URL constructor if you want to parse a complete URL.

const url = new URL('https://example.com?q1=1&q2=2');
console.log(url.searchParams.has('q3'))
console.log(url.searchParams.has('q2'))
console.log(url.searchParams.has('q1'))

answered Jan 30, 2023 at 10:37

Quentin

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