Python - Converting Hex to INT/CHAR

Question

I am having some difficulty changing a hex to an int/char (char preferably). Via the website; http://home2.paulschou.net/tools/xlate/ I enter the hex of C0A80026 into the hex box, in the DEC / CHAR box it correctly outputs the IP I expected it to contain.

This data is being pulled from an external database and I am not aware how it is being saved so all I have to work with is the hex string itself.

I have tried using the binascii.unhexlify function to see if I could decode it but I fear that I may not have a great enough understanding of hex to appreciate what I am doing.

Attemping to print just using an int() cast also has not produced the required results. I need some way to convert from that hex string (or one similar) to the original IP.

UPDATE: For anyone who comes across this in the future I modified the below answer slightly to provide an exact printout as an IP by using;

dec_output = str(int(hex_input[0:2], 16)) + "." +  str(int(hex_input[2:4], 16)) + "." + str(int(hex_input[4:6], 16)) + "." + str(int(hex_input[6:8], 16))

Please explain exactly how the duplication question is not a duplicate. Details matter. "doesn't work with my problem" is too vague to mean anything. — S.Lott
– S.Lott, Commented Sep 29, 2011 at 10:46
Sorry, I assumed you had compared them already. My problem is related to decoding hex into an IP address which the other question does not cover. Also although I do not know a great deal about hex or python there are no related questions which suggests that our similarity ends at trying to decode hex but both trying to reach two different ends — Draineh
– Draineh, Commented Sep 29, 2011 at 11:12
It helps to avoid all assumptions. I still don't understand why the supplied question is not the answer to your question because (1) I don't understand the nuances of your question and (2) I don't understand the gaps in your knowledge. Rather than assume, please update your question to detail -- specifically -- why a widely-accepted existing answer isn't appropriate for this. Details matter. And updates to the question are better than comments. — S.Lott
– S.Lott, Commented Sep 29, 2011 at 12:57

Cat Plus Plus · Accepted Answer · 2011-09-29 09:27:22Z

13

If you want to get 4 separate numbers from this, then treat it as 4 separate numbers. You don't need binascii.

hex_input  = 'C0A80026'
dec_output = [
    int(hex_input[0:2], 16), int(hex_input[2:4], 16),
    int(hex_input[4:6], 16), int(hex_input[6:8], 16),
]
print dec_output # [192, 168, 0, 38]

This can be generalised, but I'll leave it as an exercise for you.

answered Sep 29, 2011 at 9:27

Cat Plus Plus

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Comments

Nick Dandoulakis · Accepted Answer · 2011-09-29 09:54:03Z

9

A simple way

>>> s = 'C0A80026'
>>> map(ord, s.decode('hex'))
[192, 168, 0, 38]
>>>

if you prefer list comprehensions

>>> [ord(c) for c in s.decode('hex')]
[192, 168, 0, 38]
>>>

edited Sep 29, 2011 at 9:54

answered Sep 29, 2011 at 9:33

Nick Dandoulakis

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1 Comment

neil Over a year ago

Nice one. I'd personally write it as a list comprehension, but that is purely taste. I like the use of decode and ord.

JC Plessis · Accepted Answer · 2011-09-29 09:32:00Z

5

You might also need the chr function:

chr(65) => 'A'

answered Sep 29, 2011 at 9:32

JC Plessis

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jnhghy - Alexandru Jantea Over a year ago

chr accepts only integers the question states clearly that the user needs to convert a hex in an int/char (not an int to char) and chr accepts only integers so this is not a solution.

MaKiPL · Accepted Answer · 2018-04-24 12:48:03Z

4

For converting hex-string to human readable string you can escape every HEX character like this:

>>> '\x68\x65\x6c\x6c\x6f'
'hello'

from string you can easily loop to INT list:

>>> hextoint = [ord(c) for c in '\x68\x65\x6c\x6c\x6f']
>>> _
[104, 101, 108, 108, 111]

Your example:

>>> [ord(c) for c in '\xC0\xA8\x00\x26']
[192, 168, 0, 38]

answered Apr 24, 2018 at 12:48

MaKiPL

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Comments

unutbu · Accepted Answer · 2011-09-29 09:38:29Z

3

>>> htext='C0A80026'
>>> [int(htext[i:i+2],16) for i in range(0,len(htext),2)]
# [192, 168, 0, 38]

edited Sep 29, 2011 at 9:38

answered Sep 29, 2011 at 9:33

unutbu

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bluish · Accepted Answer · 2011-10-10 13:40:14Z

0

I hope it's what you expect:

hex_val = 0x42424242     # hexadecimal value
int_val = int(hex_val)   # integer value
str_val = str(int_val)   # string representation of integer value

edited Oct 10, 2011 at 13:40

bluish

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answered Sep 29, 2011 at 9:26

Manuel Leduc

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1 Comment

Cat Plus Plus Over a year ago

Literal 0x4242422 already creates an integer, int(hex_val) is redundant.

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